a .415 kg baseball is pitched at 42 m/s. the batter hits it horizontally to the pitcher at 58 m/s.
a) find the change in momentum of the ball.
b) if the ball and bat were in contact for 4.6*10^-4 s what would be the average force while they touched?
changemomentum=mass*changevelocty=
= mass*(vf-vi)=mass(-58-42)
force*time=change of momentum
To find the change in momentum of the baseball, we can use the equation:
Change in momentum = Final momentum - Initial momentum
a) To calculate the initial momentum, we can use the formula:
Initial momentum = Mass * Initial velocity
Given:
Mass (m) = 0.415 kg
Initial velocity (v₁) = 42 m/s
Initial momentum = 0.415 kg * 42 m/s
To calculate the final momentum, we use the same formula:
Final momentum = Mass * Final velocity
Given:
Mass (m) = 0.415 kg
Final velocity (v₂) = 58 m/s
Final momentum = 0.415 kg * 58 m/s
Now, we can calculate the change in momentum:
Change in momentum = Final momentum - Initial momentum
b) To find the average force, we can use the equation:
Average force = Change in momentum / Time
Given:
Change in momentum (Δp) = Final momentum - Initial momentum
Time (t) = 4.6 * 10^(-4) s
Average force = (Final momentum - Initial momentum) / Time
Now we have all the information needed to calculate the change in momentum and the average force. Plugging in the values into the equations will give us the final answers.