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March 25, 2017

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Calculate the volume of carbon dioxide produced from .025 g of aluminum carbonate and excess HCl at 25 degrees c and 745 toor according to the following reaction:
Al(2)(CO(3)(3)) (aq) + HCl (aq) ----- AlCl(3) (aq) + H(2)O + CO(2) (g)

im using the numbers in () to show a number that is really little beside the numbers.

  • College Chemistry - ,

    PV=nRT

    P=745 Torr/760 Torr = 0.98atm
    V=?
    n= 0.025g of Al/ 26.98g/mol of Al
    R=0.0821
    T=298K


    V= (0.0009266*0.0821*298)/0.98
    V=0.0231L

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