Posted by **Art** on Monday, January 31, 2011 at 2:19am.

A runner X ran the mile race in 4.25 sec. Another runner Y requires 4.55 sec to run the distance. If they start out together and maintain their normal speeds, how far apart will they be at the finish of the race?

- physics -
**Henry**, Tuesday, February 1, 2011 at 10:20pm
1 Mile = 1600 Meters.

V1 = 1600M / 4.55s = 351.65m/s = Mr X's speed.

At the end of 4.25s, Mr.Y has run 1600

meters.

During the same time, Mr. X runs:

d = 351.65m/s * 4.25s = 1494.5 meters.

1600 -1494.5 = 105.5m apart at end of race.

## Answer This Question

## Related Questions

- physics - 2 runners accelerate from rest to their top speeds. The 1st runner pat...
- math/physics - During a race, one runner runs at a 6 min/mi pace and another ...
- Intro Physics Help - A runner in a relay race is required to run a distance of ...
- Physics Again - In 1954 the English runner Roger Bannister broke the four minute...
- Physics - A runner is jogging at a steady 8.4 km/hr. When the runner is 2.6 km ...
- math - It took a faster runner 10 sec. longer to run a distance of 1500 m than ...
- Physics - Near the end of a marathon race, the first two runners are separated ...
- physics - In an 8.00 race, one runner runs at a steady 11.8 and another runs at ...
- Maths - Three runners run a 10 metre race. Each runner runs according to the ...
- physics - (A)A runner is jogging at a steady 7.7 km/hr. when the runner is 3.9 ...

More Related Questions