Posted by Art on Monday, January 31, 2011 at 2:19am.
A runner X ran the mile race in 4.25 sec. Another runner Y requires 4.55 sec to run the distance. If they start out together and maintain their normal speeds, how far apart will they be at the finish of the race?

physics  Henry, Tuesday, February 1, 2011 at 10:20pm
1 Mile = 1600 Meters.
V1 = 1600M / 4.55s = 351.65m/s = Mr X's speed.
At the end of 4.25s, Mr.Y has run 1600
meters.
During the same time, Mr. X runs:
d = 351.65m/s * 4.25s = 1494.5 meters.
1600 1494.5 = 105.5m apart at end of race.
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