A boat starts at point A, moves 3 km due north, then 2 km due east, then 1 km due south, and then 4 km due east to point B. Find the distance AB.
2X5^1/2
I DON'T KNOW.... ;)... PLZZZ U GUVE ME ANSWER
To find the distance AB, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
Let's break down the boat's movement:
1. The boat moves 3 km due north from point A. This creates a right triangle with one leg measuring 3 km.
2. The boat then moves 2 km due east. This creates another right triangle with one leg measuring 2 km.
3. Next, the boat moves 1 km due south. This cancels out 1 km of the northward movement, so we end up with a horizontal line, which we can ignore.
4. Finally, the boat moves 4 km due east, completing the final leg of the triangle with a length of 4 km.
Now, we have a right triangle with two legs measuring 3 km and 4 km. We need to find the hypotenuse, which represents the distance AB.
Using the Pythagorean theorem, we can calculate the length of the hypotenuse (AB):
AB^2 = (3^2) + (4^2)
AB^2 = 9 + 16
AB^2 = 25
Taking the square root of both sides to solve for AB: AB = √25 = 5
Therefore, the distance AB is 5 kilometers.