When you freeze water, 80 calories of heat are released into the surroundings for every gram of water that freezes. This is known as the "latent heat of fusion" of water, which is 80 cal/g. Heat of fusion is a characteristic property. Theoretically, if you could "capture" all the heat that is released into a tightly sealed container, by freezing 10 gallons of water: How much heat would you be obtaining?

One gallon of water weighs 8.35 lb and has a mass of

8.35 lbm*454 g/lbm = 3791 g

Multiply that by the heat of fusion (per gram)

Your answer will be in calories.

To determine the amount of heat that would be obtained by freezing 10 gallons of water, we need to convert the volume from gallons to grams, and then multiply it by the latent heat of fusion of water.

First, let's convert gallons to grams. The conversion factor is as follows:
1 gallon = 3785.41 grams

Therefore, 10 gallons of water is equal to 10 x 3785.41 grams = 37,854.1 grams.

Now, we can calculate the amount of heat obtained by multiplying the mass in grams by the latent heat of fusion of water:
Heat obtained = Mass of water x Latent heat of fusion

Heat obtained = 37,854.1 grams x 80 cal/g

By multiplying these two values, we get the amount of heat obtained:
Heat obtained = 3,028,328 cal.

Therefore, by freezing 10 gallons of water, you would obtain approximately 3,028,328 calories of heat.