Posted by **amanda** on Sunday, January 30, 2011 at 9:29pm.

We just started logarithms and exponential functions, and I'm kind of getting the gist but not really. Here is what I tried on one of the homework problems:

2^X=4^X+1

1)2^X=(2^2)^X+1

2)x=x+1

3)0=1 or no solutions

I wasn't sure what to do between steps 1 and 2. Thanks!!

- Algebra 2/Trig -
**Reiny**, Sunday, January 30, 2011 at 9:34pm
If the question is the way you typed it, it is a nasty question.

I am pretty sure you meant

2^x = 4^(x+1)

did you notice that both bases are powers of 2 ?

2^x = (2^2)^(x+1)

2^x = 2^(2x+2)

then 2x + 2 = x

x = -2

- Algebra 2/Trig -
**amanda**, Sunday, January 30, 2011 at 9:39pm
I see where the extra step was! Thanks so much!

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