Saturday

August 2, 2014

August 2, 2014

Posted by **amanda** on Sunday, January 30, 2011 at 9:29pm.

2^X=4^X+1

1)2^X=(2^2)^X+1

2)x=x+1

3)0=1 or no solutions

I wasn't sure what to do between steps 1 and 2. Thanks!!

- Algebra 2/Trig -
**Reiny**, Sunday, January 30, 2011 at 9:34pmIf the question is the way you typed it, it is a nasty question.

I am pretty sure you meant

2^x = 4^(x+1)

did you notice that both bases are powers of 2 ?

2^x = (2^2)^(x+1)

2^x = 2^(2x+2)

then 2x + 2 = x

x = -2

- Algebra 2/Trig -
**amanda**, Sunday, January 30, 2011 at 9:39pmI see where the extra step was! Thanks so much!

**Related Questions**

Trigonometry (Logarthims) - Give checks to the following two questions Use ...

Logarithms - log4(10)=x Im having trouble getting started here with this ...

Math - Use your knowledge of exponents to solve. a) 1/2^x=1/(x+2) b) 1/2^x>1/...

Algebra please help! - I'm very confused with what I'm learning about right now...

5th grade math - My daughter must correct the problems that she has gotten wrong...

Life - Okay, so this isn't homework help or anything but can someone help me ...

Math - Hi, I am getting very frustrated. I am doing an online homework for ...

algebra - How do I do substitution equations out of the equations in the system...

Chemistry - One last question...even though no one seems to be willing to help ...

Algebra - Right now we are learning about functions, relations, etc. and I am ...