We just started logarithms and exponential functions, and I'm kind of getting the gist but not really. Here is what I tried on one of the homework problems:
3)0=1 or no solutions
I wasn't sure what to do between steps 1 and 2. Thanks!!
Algebra 2/Trig - Reiny, Sunday, January 30, 2011 at 9:34pm
If the question is the way you typed it, it is a nasty question.
I am pretty sure you meant
2^x = 4^(x+1)
did you notice that both bases are powers of 2 ?
2^x = (2^2)^(x+1)
2^x = 2^(2x+2)
then 2x + 2 = x
x = -2
Algebra 2/Trig - amanda, Sunday, January 30, 2011 at 9:39pm
I see where the extra step was! Thanks so much!