Posted by **thaokieu** on Sunday, January 30, 2011 at 8:04pm.

Before starting this problem, review Conceptual Example 7. The force vector A has a magnitude of 79.0 newtons (N) and points due east. The force vector B has a magnitude of 107 N and points 75.0 ° north of east. Find the (a) magnitude and (b) direction of A - B. (Give the direction as a positive angle with respect to due east). Find the (c) magnitude and (d) direction of B - A. (Give the direction as a positive angle with respect to due west).

- physics -
**Henry**, Tuesday, February 1, 2011 at 8:22pm
Given: A = 79N, East; B = 107N @ 75deg.

a. X = hor. = 79 - 107cos75,

X = 79 - 27.7 = 51.3N.

Y = ver. = 0 - 107sin75,

Y = 0 - 103.4 = -103.4N.

M^2 = X^2 + Y^2,

M^2 = (51.3)^2 + (-103.4)^2,

M^2 = 2631.7 + 10691.6 = 13323,

M = 115.4N Magnitude of A-B.

b. tanA = Y/X = -103.4 / 51.3 = -2.015,

A = -63.6Deg. = 63.6deg South of East = Direction of A-B.

Use the above procedure for B-A.

Mag.= X/cosA = 106.7 / cos44.1 = 148.6N.

b. A = 79N,

B = 107N@75deg. = 107cos75 + i107sin75,

B = 27.7 + i103.4.

A - B = A to B = (27.7 + i103.4) -79,

A to B = -51.3 + i103.4

tan(theta) = 103.4 / -51.3 = -2.0156,

Theta = -63.6deg = 63.6deg South of East.

c.

- physics -
**Henry**, Tuesday, February 1, 2011 at 8:28pm
OOPS!!

Ignore data shown after part b.

It is incorrect.

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