Posted by Chloe Mack on Sunday, January 30, 2011 at 7:57pm.
A surveyor stakes out points A and B on sides of a building. Point C on the side of the building is 300 feet from A and 440 feet from B. Angle ACB measures 38 degrees. What is the distance from A to B?

PreCalculusTrig  Henry, Tuesday, February 1, 2011 at 11:54am
Use the Law of Cosines to solve triangle ABC:
cosC = (a^2 + b^2  c^2) / 2ab.
cos38=((440)^2+(300)^2c^2)/2*440*300,
0.7880 = (283600  c^2) / 264000,
Cross multiply:
c^2 + 283600 = 208032,
c^2 = 208032  283600,
c^2 =  75568,
c^2 = 75568,
c = 275ft. = Distance from A to B.
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