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April 18, 2014

April 18, 2014

Posted by **Chloe Mack** on Sunday, January 30, 2011 at 7:57pm.

- Pre-Calculus-Trig -
**Henry**, Tuesday, February 1, 2011 at 11:54amUse the Law of Cosines to solve triangle ABC:

cosC = (a^2 + b^2 - c^2) / 2ab.

cos38=((440)^2+(300)^2-c^2)/2*440*300,

0.7880 = (283600 - c^2) / 264000,

Cross multiply:

-c^2 + 283600 = 208032,

-c^2 = 208032 - 283600,

-c^2 = - 75568,

c^2 = 75568,

c = 275ft. = Distance from A to B.

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