Posted by sir on .
A weight of 50.0 N is suspended from a spring that has a force constant of 190 N/m. The system is undamped and is subjected to a harmonic driving force of frequency 10.0 Hz, resulting in a forcedmotion amplitude of 4.00 cm. Determine the maximum value of the driving force.
N

physics 
Damon,
Force = m a
w = 2 pi f = 62.8 radians/second
Forcing function kx = m d^2x/dt^2
let forcing function = F sin wt
so F sin w t = k x + m d^2x/dt^2
let resulting motion be x = a sin wt + b cos w t
then
d^2x/dt^2 =  a w^2 sin wt  bw^2 cos wt
so (s is sin and c is cos)
Fsin wt=k(a s wt+b c wt)m(a w^2 s wtb w^2 c wt)
sin terms
F = k a  m a w^2
F = a (kw^2 m)
but
a = .04 meters
k = 190 N/m
m = 50/9.8 = 5.1 kg
w^2 = 3944 rad^2/s^2
so
F = .04(190  3944*5.1)
= 797N
the cos terms give you the natural frequency motion at w = sqrt(k/m)
note we are driving at about 60 rad/sec whereas the natural frequency is about 6 rad/sec so it is not going to move much for a large force.