Saturday

December 20, 2014

December 20, 2014

Posted by **Rachel** on Sunday, January 30, 2011 at 3:26pm.

y=sqrt*(x+2)

y=1/(1+x)

I got

2/3(8)-ln3-2/3(sqrt*8)

can someone please verify this?

- Calculus -
**helper**, Sunday, January 30, 2011 at 5:11pm2/3(8)-ln3-2/3(sqrt*8)

My answer,

16/3 - ln 3 - 4/3(sqrt(2))

You have 16/3,

2/3 (8) = 16/3

Where you went wrong,

You have, 2/3 (sqrt(8))

It should be,

2/3 (0 + 2)^3/2

2/3 (2)^3/2

2/3 (sqrt(2))^3

2/3 (2(sqrt(2)))

4/3 (sqrt(2))

- Calculus -
**let me help**, Sunday, January 30, 2011 at 5:33pmPerfect, thanks!

I agree that your answer is more simplified..

but my answer is definitely not wrong because

2/3(sqrt(8)) and 4/3(sqrt(2)) are the same.

Because.. 8=4x2 and sqrt of 4 is 2.. so you take 2 out of the sqrt to be 2. 2x2 is 4. so you end up with 4/3(sqrt(2)). Do you agree?

- Calculus -
**helper**, Sunday, January 30, 2011 at 5:51pmI guess it depends on your teacher, because

(2)^3/2 means (sqrt(2))^3

I've never seen anyone interpret this as

(sqrt(2^3)).

The first way will always get you the correct, simplified answer. If I were you, I would get in the habit of doing this the first way.

Radicals should always be in the lowest terms. Any teacher I had would take off half credit for your answer.

Good luck.

**Answer this Question**

**Related Questions**

Check my CALCULUS answers please! - Any short explanation for things I got ...

Math Help please!! - Could someone show me how to solve these problems step by ...

Calculus - Evaluate the indefinite integral: 8x-x^2. I got this but I the ...

Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...

Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...

math calculus please help! - l = lim as x approaches 0 of x/(the square root of...

Math(Roots) - sqrt(24) *I don't really get this stuff.Can somebody please help ...

math,algebra,help - Directions are simplify by combining like terms. x radiacal ...

MATH - I need to simply this equation, but I got stuck. h/(4-sqrt(16+h)) = y ...

Calculus - In these complex exponential problems, solve for x: 1)e^(i*pi) + 2e^(...