Posted by Rachel on Sunday, January 30, 2011 at 3:26pm.
Find the area enclosed by the following functions from x=0 to x=2:
y=sqrt*(x+2)
y=1/(1+x)
I got
2/3(8)ln32/3(sqrt*8)
can someone please verify this?

Calculus  helper, Sunday, January 30, 2011 at 5:11pm
2/3(8)ln32/3(sqrt*8)
My answer,
16/3  ln 3  4/3(sqrt(2))
You have 16/3,
2/3 (8) = 16/3
Where you went wrong,
You have, 2/3 (sqrt(8))
It should be,
2/3 (0 + 2)^3/2
2/3 (2)^3/2
2/3 (sqrt(2))^3
2/3 (2(sqrt(2)))
4/3 (sqrt(2))

Calculus  let me help, Sunday, January 30, 2011 at 5:33pm
Perfect, thanks!
I agree that your answer is more simplified..
but my answer is definitely not wrong because
2/3(sqrt(8)) and 4/3(sqrt(2)) are the same.
Because.. 8=4x2 and sqrt of 4 is 2.. so you take 2 out of the sqrt to be 2. 2x2 is 4. so you end up with 4/3(sqrt(2)). Do you agree?

Calculus  helper, Sunday, January 30, 2011 at 5:51pm
I guess it depends on your teacher, because
(2)^3/2 means (sqrt(2))^3
I've never seen anyone interpret this as
(sqrt(2^3)).
The first way will always get you the correct, simplified answer. If I were you, I would get in the habit of doing this the first way.
Radicals should always be in the lowest terms. Any teacher I had would take off half credit for your answer.
Good luck.
Answer This Question
Related Questions
 Check my CALCULUS answers please!  Any short explanation for things I got wrong...
 Math Help please!!  Could someone show me how to solve these problems step by ...
 linear algebra urgent  For the orthogonal matrix A = 1/sqrt(2) 1/sqrt(2) 1/(...
 Calculus  Evaluate the indefinite integral: 8xx^2. I got this but I the ...
 Math/Calculus  Solve the initialvalue problem. Am I using the wrong value for ...
 Calculus  Please look at my work below: Solve the initialvalue problem. y'' + ...
 Calculus check  Given f(x)=x^4(2x^215). On what interval(s) is the graph of f ...
 math calculus please help!  l = lim as x approaches 0 of x/(the square root of...
 Math(Roots)  sqrt(24) *I don't really get this stuff.Can somebody please help ...
 math,algebra,help  Directions are simplify by combining like terms. x radiacal ...
More Related Questions