an isosceles triangle has a perimeter of 136 inches. If one of its equal sides measures 42 inches, what is the measure of the non-equal side?

Let the sides be A, A and B.

A being one of the equal sides, and B the third side.

"an isosceles triangle has a perimeter of 136 inches."

means that
A+A+B = 136 .... (1)

and

"If one of its equal sides measures 42 inches"

means A=42, this makes equation (1):

42+42+B = 136

and we look for the value of B.

Can you take it from here?

b=52

To find the measure of the non-equal side of an isosceles triangle, where the perimeter and one equal side are known, follow these steps:

Step 1: The perimeter of an isosceles triangle is the sum of all three sides. So, if the perimeter is 136 inches, the sum of the three sides is 136 inches.

Step 2: For an isosceles triangle, two sides are equal, while the third side (non-equal side) has a different measurement. Let's assume that the measure of the non-equal side is x inches.

Step 3: Since we know that one equal side measures 42 inches, we can substitute it into the equation. The sum of the three sides is 42 + 42 + x = 136 inches.

Step 4: Simplify the equation: 84 + x = 136.

Step 5: Solve for x by subtracting 84 from both sides of the equation: x = 136 - 84.

Step 6: Calculate x: x = 52.

Therefore, the measure of the non-equal side is 52 inches.