Posted by **Emily** on Sunday, January 30, 2011 at 10:58am.

A golf ball is hit with an initial angle of 54.7o with respect to the horizontal and an initial velocity of 85.1 mph. It lands a distance of 104.3 m away from where it was hit. By how much did the effects of wind resistance, spin, and so forth reduce the range of the golf ball from the ideal value?

- Physics -
**drwls**, Sunday, January 30, 2011 at 12:37pm
The ideal range is

(Vo^2/g)*sin(2*54.7)

Subtract 104.3 m from that for the answer.

You will have to convert 104.3 mph to m/s before applying the formula.

That is an extremely slow speed for a golf ball. A reasonably healthy person can throw a golf ball at that speed.

- Physics (correction) -
**drwls**, Sunday, January 30, 2011 at 12:41pm
I meant 85.1 mph for the speed that must be cnverted to m/s

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