Posted by Emily on Sunday, January 30, 2011 at 10:58am.
A golf ball is hit with an initial angle of 54.7o with respect to the horizontal and an initial velocity of 85.1 mph. It lands a distance of 104.3 m away from where it was hit. By how much did the effects of wind resistance, spin, and so forth reduce the range of the golf ball from the ideal value?

Physics  drwls, Sunday, January 30, 2011 at 12:37pm
The ideal range is
(Vo^2/g)*sin(2*54.7)
Subtract 104.3 m from that for the answer.
You will have to convert 104.3 mph to m/s before applying the formula.
That is an extremely slow speed for a golf ball. A reasonably healthy person can throw a golf ball at that speed.

Physics (correction)  drwls, Sunday, January 30, 2011 at 12:41pm
I meant 85.1 mph for the speed that must be cnverted to m/s
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