trig
posted by Anonymous .
Given that sin x =  ã2/2 and that cos x is negative, find the other functions of x and the value of x.
can you explain how this problem can be solved please.

Do you mean (sqrt(2))/2 ?

yes
okay i know that this is in the 3rd quadrant with reference angle 45
so i understand the first part but what i don't get is how i can find the value can you please explain. 
sides of triangle are sqrt 2, sqrt 2 , 2 so
cos x also = sqrt 2 / 2
tan = sin / cos
sec = 1/cos
csc = 1/sin
ctn = 1/tan 
sin = sqrt 2 / 2
cos = sqrt 2 / 2
tan = 1
cot = 1
sec = sqrt 2
csc = sqrt 2
is that right ?
okay now how can i find the value? 
yes. Sqrt 2 is approximately 1.41

x = 180 + 45 in degrees
= (1 1/4) pi in radians 
thanks for your time but they are also asking for the value of x which i think they mean the value of x in degrees ??

thank you.

x = 225 degrees