Posted by **Anonymous** on Sunday, January 30, 2011 at 12:49am.

Given that sin x = - 2/2 and that cos x is negative, find the other functions of x and the value of x.

can you explain how this problem can be solved please.

- trig -
**helper**, Sunday, January 30, 2011 at 1:16am
Do you mean -(sqrt(2))/2 ?

- trig -
**Anonymous**, Sunday, January 30, 2011 at 1:39am
yes

okay i know that this is in the 3rd quadrant with reference angle 45

so i understand the first part but what i dont get is how i can find the value can you please explain.

- trig -
**Damon**, Sunday, January 30, 2011 at 1:48am
sides of triangle are sqrt 2, sqrt 2 , 2 so

cos x also = -sqrt 2 / 2

tan = sin / cos

sec = 1/cos

csc = 1/sin

ctn = 1/tan

- trig -
**Anonymous**, Sunday, January 30, 2011 at 1:55am
sin = -sqrt 2 / 2

cos = -sqrt 2 / 2

tan = 1

cot = 1

sec = -sqrt 2

csc = -sqrt 2

is that right ?

okay now how can i find the value?

- trig -
**Damon**, Sunday, January 30, 2011 at 2:00am
yes. Sqrt 2 is approximately 1.41

- trig -
**Damon**, Sunday, January 30, 2011 at 2:02am
x = 180 + 45 in degrees

= (1 1/4) pi in radians

- trig -
**Anonymous**, Sunday, January 30, 2011 at 2:05am
thanks for your time but they are also asking for the value of x which i think they mean the value of x in degrees ??

- trig -
**Anonymous**, Sunday, January 30, 2011 at 2:08am
thank you.

- trig -
**helper**, Sunday, January 30, 2011 at 1:24pm
x = 225 degrees

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