Posted by Anonymous on Sunday, January 30, 2011 at 12:49am.
Given that sin x = - ã2/2 and that cos x is negative, find the other functions of x and the value of x.
can you explain how this problem can be solved please.
trig - helper, Sunday, January 30, 2011 at 1:16am
Do you mean -(sqrt(2))/2 ?
trig - Anonymous, Sunday, January 30, 2011 at 1:39am
okay i know that this is in the 3rd quadrant with reference angle 45
so i understand the first part but what i don't get is how i can find the value can you please explain.
trig - Damon, Sunday, January 30, 2011 at 1:48am
sides of triangle are sqrt 2, sqrt 2 , 2 so
cos x also = -sqrt 2 / 2
tan = sin / cos
sec = 1/cos
csc = 1/sin
ctn = 1/tan
trig - Anonymous, Sunday, January 30, 2011 at 1:55am
sin = -sqrt 2 / 2
cos = -sqrt 2 / 2
tan = 1
cot = 1
sec = -sqrt 2
csc = -sqrt 2
is that right ?
okay now how can i find the value?
trig - Damon, Sunday, January 30, 2011 at 2:00am
yes. Sqrt 2 is approximately 1.41
trig - Damon, Sunday, January 30, 2011 at 2:02am
x = 180 + 45 in degrees
= (1 1/4) pi in radians
trig - Anonymous, Sunday, January 30, 2011 at 2:05am
thanks for your time but they are also asking for the value of x which i think they mean the value of x in degrees ??
trig - Anonymous, Sunday, January 30, 2011 at 2:08am
trig - helper, Sunday, January 30, 2011 at 1:24pm
x = 225 degrees
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