physics
posted by Anonymous on .
A 65.0Ù resistor is connected in parallel with a 117.0Ù resistor. This parallel group is connected in series with a 22.0Ù resistor. The total combination is connected across a 15.0V battery
Find the current in the 117.0Ù resistor.
Find the power dissipated in the 117.0Ù resistor

total resistance parallel branch:
Req=65*117/(182)= 41.8 ohms
total circuit resistance: 41.8+22=63.8 ohms
total current: 15/63.8=.235a
voltage across the parallel branch:
.235*41.8=9.82 volts
current in 117 = 9.82/117 amps