What is the permineter and area of a rectangle that has a length of 8 feet and width of 3 feet.
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P = 2L + 2W
P = 2(8) + 2(3)
P = ?
A = LW
A = 8 * 3
A = ?
To find the perimeter of a rectangle, you can use the formula P = 2l + 2w, where P represents the perimeter, l represents the length, and w represents the width.
In this case, the length (l) is 8 feet and the width (w) is 3 feet. Plugging these values into the formula, we get:
P = 2(8) + 2(3)
P = 16 + 6
P = 22
Therefore, the perimeter of the rectangle is 22 feet.
To find the area of a rectangle, you can use the formula A = l * w, where A represents the area, l represents the length, and w represents the width.
In this case, the length (l) is still 8 feet and the width (w) is still 3 feet. Plugging these values into the formula, we get:
A = 8 * 3
A = 24
Therefore, the area of the rectangle is 24 square feet.