Posted by rock on Friday, January 28, 2011 at 10:33pm.
I got part a) 166.25
b)?
(b) Multiply the pipe cross sectional area (pi*(0.06)^2/4 m^2) by the velocity of the water leaving. You will get a volume flow rate in m^3/s.
The water flow velocity can be obtained from the Bernoulli equation. It depends upon d, not D.
v = sqrt(2 g d)
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