A 10 kg block is allowed to slide down a ramp with uk = 0.15.
a. What is the value of the frictional force opposing the block's slide down the ramp?
b. What is the acceleration of the block?
a.Fk=(u)Fn
Fk=(0.15)9.40=1.41 N
10cos(20)=9.40=Fn
b.Fnet=(mass)a
1.41 N=(10 kg) a
a=.141 m/s^2
Good work. I almost didn't see the decimal point in front of .141
It would be better to write it as 0.141 m/s^2. It is easier to read that way.
To calculate the frictional force opposing the block's slide down the ramp and the acceleration of the block, you will need to use the following formulas:
1. Frictional force (Ff) = coefficient of friction (uk) * normal force (Fn)
2. Normal force (Fn) = mass (m) * gravitational acceleration (g)
3. Acceleration (a) = net force (Fnet) / mass (m)
Given:
- Mass of the block (m) = 10 kg
- Coefficient of kinetic friction (uk) = 0.15
a. Calculation of the frictional force opposing the slide:
First, calculate the normal force (Fn) acting on the block. The normal force is equal to the weight of the block, which is the product of its mass and gravitational acceleration.
Fn = m * g
Fn = 10 kg * 9.8 m/s^2
Fn = 98 N
Now, use the formula for frictional force:
Ff = uk * Fn
Ff = 0.15 * 98 N
Ff = 14.7 N
Therefore, the frictional force opposing the block's slide down the ramp is 14.7 N.
b. Calculation of the acceleration of the block:
To find the acceleration, we need to calculate the net force acting on the block. The net force is the difference between the gravitational force acting down the ramp and the frictional force opposing the slide.
Net force (Fnet) = mg - Ff
Fnet = m * g - Ff
Fnet = 10 kg * 9.8 m/s^2 - 14.7 N
Fnet = 98 N - 14.7 N
Fnet = 83.3 N
Now, use the formula for acceleration:
a = Fnet / m
a = 83.3 N / 10 kg
a = 8.33 m/s^2
Therefore, the acceleration of the block sliding down the ramp is 8.33 m/s^2.
I don't understand why the normal force is 9.4. If the object weighs 10 kg, the Fg in the y direction should be 92.1N, correct which would make the Fn 92.1N as well.
I agree with Claire. My final answer for the acceleration was 1.97m/s^2
After you have learned how to compute the frictional force, and applied
F(net) = ma in the downward direction along the ramp, feel free to post your work for critical evaluation.
We are not going to do it for you.