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March 29, 2017

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A 10 kg block is allowed to slide down a ramp with uk = 0.15.

a. What is the value of the frictional force opposing the block's slide down the ramp?
b. What is the acceleration of the block?

  • Physics - ,

    After you have learned how to compute the frictional force, and applied
    F(net) = ma in the downward direction along the ramp, feel free to post your work for critical evaluation.

    We are not going to do it for you.

  • Physics - ,

    a.Fk=(u)Fn
    Fk=(0.15)9.40=1.41 N
    10cos(20)=9.40=Fn

    b.Fnet=(mass)a
    1.41 N=(10 kg) a
    a=.141 m/s^2

  • Physics - ,

    Good work. I almost didn't see the decimal point in front of .141

    It would be better to write it as 0.141 m/s^2. It is easier to read that way.

  • Physics - ,

    I don't understand why the normal force is 9.4. If the object weighs 10 kg, the Fg in the y direction should be 92.1N, correct which would make the Fn 92.1N as well.

  • Physics - ,

    ,k

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