Math
posted by Rachel .
i) The two lines 4x6y=5, and 7x+6y=7 intersect at the point where x= and y=?
ii) If the line 7x+ky=7 is parallel to 4x6y=5, then what is the value of k? Answer: k = ?

The two equations are easy to solve, just add up the two equations and the y term will drop out to get
11x = 2
x = 2/11
sub back into the second (or the first) to get
7(2/11) + 6y = 7
times 11
14 + 66y = 77
66y = 63
y = 63/66 = 21/22
slope of first line = 7/k
slope of 2nd line = 4/6 = 2/3
so 7/k = 2/3
crossmultiply
2k = 21
k = 21/2