1.Robin has a certain number of dimes in his pocket. If the dimes were pennies, he would have $1.08 less than he has now. How many dimes does he have in his pocket?

Duplicate post. Answered below

To solve this problem, we'll need to use algebra. Let's first assume that Robin has x number of dimes in his pocket.

Now, let's consider the condition given in the problem. If the dimes were pennies, Robin would have $1.08 less than he has now.

Since 1 dollar is equivalent to 100 cents, we can express the value of the dimes as 10x cents. If we convert this value to pennies, it becomes 1000x pennies.

According to the problem, if the dimes were pennies, Robin would have $1.08 less. In other words, the value of the dimes minus $1.08 is equal to the value of the dimes if they were pennies:

10x - 1.08 = 1000x

Now, we can solve for x:

10x - 1000x = 1.08
-990x = 1.08
x = 1.08 / -990
x ≈ -0.00109

This negative value implies that our assumption was incorrect. It is not possible to have a negative number of dimes. Therefore, there is no solution to this problem and we cannot determine the number of dimes Robin has in his pocket based on the given information.