If the reaction below proceeds with a 96.8% yield, how many kilograms of CaSO4 are formed when 5.27 kg SO2 reacts with an excess of CaCO3 and O2?

2 CaCO3(s) + 2 SO2(g) + O2(g) 2 CaSO4(g) + 2 CO2(g)

Here is a worked example of a similar problem. Just follow the steps.

http://www.jiskha.com/science/chemistry/stoichiometry.html
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why is the enthalpy chance for a reaction proportional to the quantity of reactants

To calculate the amount of CaSO4 formed, we need to follow these steps:

1. Convert the given mass of SO2 to moles.
2. Use the balanced equation to determine the mole ratio between SO2 and CaSO4.
3. Convert the moles of CaSO4 to mass.

Let's go through each step in detail:

Step 1: Convert mass of SO2 to moles.
Given: Mass of SO2 = 5.27 kg

To convert mass to moles, we need to use the molar mass of SO2.
The molar mass of SO2 is calculated as follows:
Sulfur (S) = 32.07 g/mol
Oxygen (O) = 16.00 g/mol x 2 = 32.00 g/mol

Therefore, the molar mass of SO2 = 32.07 g/mol + 32.00 g/mol = 64.07 g/mol.

To convert the mass of SO2 to moles, we use the formula:
moles = mass / molar mass

Plugging in the values, we have:
moles of SO2 = 5.27 kg / 64.07 g/mol

Step 2: Determine the mole ratio between SO2 and CaSO4.
Looking at the balanced equation provided:
2 CaCO3(s) + 2 SO2(g) + O2(g) → 2 CaSO4(g) + 2 CO2(g)

From the equation, we can see that the ratio between SO2 and CaSO4 is 2:2. This means that for every 2 moles of SO2 reacted, 2 moles of CaSO4 are formed.

Step 3: Convert moles of CaSO4 to mass.
Now that we have the moles of SO2, we can calculate the moles of CaSO4 using the mole ratio determined in Step 2.

moles of CaSO4 = moles of SO2 (from Step 1) x (2 moles of CaSO4 / 2 moles of SO2)

Step 4: Convert moles of CaSO4 to mass.
To convert the moles of CaSO4 to mass, we use the formula:
mass = moles x molar mass

The molar mass of CaSO4 is calculated as follows:
Calcium (Ca) = 40.08 g/mol
Sulfur (S) = 32.07 g/mol
Oxygen (O) = 16.00 g/mol x 4 = 64.00 g/mol

Therefore, the molar mass of CaSO4 = 40.08 g/mol + 32.07 g/mol + 64.00 g/mol = 136.15 g/mol.

Finally, we can calculate the mass of CaSO4:
mass of CaSO4 = moles of CaSO4 (from Step 3) x molar mass of CaSO4

By following these steps, you can calculate the mass of CaSO4 formed when 5.27 kg of SO2 reacts with an excess of CaCO3 and O2, assuming a 96.8% yield.