Posted by **Please help** on Thursday, January 27, 2011 at 9:53pm.

A refrigerated truck leaves a rest stop traveling at a steady rate of 56 mi/h. A car leaves the same rest stop 1/4 h later followinf rhe truck at a steady rate of 64 mi/h. How long after the truck leaves the rest stop wil the car overtake the truck. In algebra form.

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**Reiny**, Thursday, January 27, 2011 at 9:58pm
When the car overtakes the truck, they both would have traveled the same distance, except the truck took 1/4 hour longer

let the time taken by the car be x hours

then the time taken by the truck is x+1/4 hour

distance gone by car = 64x

distance gone by truck = 56(x+1/4)

but didn't we say those distances would be equal?

let me know what you got

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**Please help**, Thursday, January 27, 2011 at 10:04pm
-2 but is that for the truck or car

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**helper**, Friday, January 28, 2011 at 12:21am
The time x cannot be negative. You must have made a mistake.

The two equations are,

distance gone by car = 64x

distance gone by truck = 56(x+1/4)

Since the distances are equal,

64x = 56(x + 1/4)

64x = 56x + 56/4

64x = 56x + 14

8x = 14

x = 1.75

From above (Reiny's explanation)

Since x = time taken by the car in hours, the car will overtake the truck in 1.75 hrs.

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**steven**, Tuesday, March 1, 2011 at 10:44pm
A computer costs $799. To add memory it costs $25 for 8 megabytes. How much memory can you add if you have at most $1,000 to spend.

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**Monica**, Thursday, December 11, 2014 at 11:48pm
It will be 2 hours u til the car catches up tot the truck.Sorry, I don't have the work. :(

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**nicholas; Nzili**, Thursday, October 22, 2015 at 6:33am
relative speed=64-56

=8mi/h

distance travelled by truck for 1/4h

=s*t=56*1/4=14mi

time spent by car in overtaking

t=d/s=14/8

=1.75hrs

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