Posted by Please help on .
A refrigerated truck leaves a rest stop traveling at a steady rate of 56 mi/h. A car leaves the same rest stop 1/4 h later followinf rhe truck at a steady rate of 64 mi/h. How long after the truck leaves the rest stop wil the car overtake the truck. In algebra form.

Math 
Reiny,
When the car overtakes the truck, they both would have traveled the same distance, except the truck took 1/4 hour longer
let the time taken by the car be x hours
then the time taken by the truck is x+1/4 hour
distance gone by car = 64x
distance gone by truck = 56(x+1/4)
but didn't we say those distances would be equal?
let me know what you got 
Math 
Please help,
2 but is that for the truck or car

Math 
helper,
The time x cannot be negative. You must have made a mistake.
The two equations are,
distance gone by car = 64x
distance gone by truck = 56(x+1/4)
Since the distances are equal,
64x = 56(x + 1/4)
64x = 56x + 56/4
64x = 56x + 14
8x = 14
x = 1.75
From above (Reiny's explanation)
Since x = time taken by the car in hours, the car will overtake the truck in 1.75 hrs. 
Math 
steven,
A computer costs $799. To add memory it costs $25 for 8 megabytes. How much memory can you add if you have at most $1,000 to spend.

Math 
Monica,
It will be 2 hours u til the car catches up tot the truck.Sorry, I don't have the work. :(

Math 
nicholas; Nzili,
relative speed=6456
=8mi/h
distance travelled by truck for 1/4h
=s*t=56*1/4=14mi
time spent by car in overtaking
t=d/s=14/8
=1.75hrs