Posted by **Esther** on Thursday, January 27, 2011 at 8:52pm.

Is there anybody out there that can give me the answer to this problem I have tried but I can't get it. I really need to turn in my work. Thank you (4,-8); 2x+5y=4

- Algebra -
**Reiny**, Thursday, January 27, 2011 at 9:17pm
You didn't state your problem.

Are you finding a new equation

parallel to the given line ?

perpendicular to the given line ?

??

- Algebra -
**helper**, Thursday, January 27, 2011 at 9:47pm
2x + 5y = 4

Add -2x to both sides

5y = -2x + 4

divide both sides by 5

y = -2/5 y + 4/5

So, slope m = -2/5

Perpendicular lines, the slopes are negative reciprocals of each other.

Slope = -2/5

m1 * m2 = -1

-2/5 * m2 = -1

m2 = -1/(-2/5)

m2 = 5/2

Now you have to find b, for the equation of the perpendicular line.

y = mx + b

m = 5/2

y = 5/2 x + b

P(4, -8)

-8 = 5/2 (4) + b

-8 = 20/2 + b

-8 = 10 + b

-18 = b

y = 5/2 x + b

y = 5/2 + -18

y = 5/2 - 18

Follow these exact steps.

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