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Chemistry

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For a solution that is 0.20 M HCN(aq) with a Ka=4.9x10^-10

a. calculate the [H+]
b. calculate the [OH-]
c. what's the pH?


Please show your work on how to solve it. Thank you

  • Chemistry -

    .............HCN ==> H^+ + CN^-
    initial....0.20M.....0.....0
    change......-x.......+x.....+x
    final.... 0.20-x......x.....x

    Ka = ((H^+)(CN^-)/(HCN)
    Substitute from the above and solve for (H^+).
    pH = -log(H^+)
    pH + pOH = pKw = 14
    Post your work if you get stuck.

  • Chemistry -

    Thanks! That was helpful.

  • Chemistry -

    thunder blew a 3-1 lead

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