Posted by Jessica on .
2X^49X^3+3X^2X5=0
Given that one root is 2+i, solve the equation.
So far I have it set up like this:
2X^49X^3+3X^2X5/X^24X+5
I don't know how to get the answer, I know that I have to use long division but when I started to try it I kept getting weird answers. Please Help

algebra 2 
PsyDAG,
Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you.