Thursday

July 24, 2014

July 24, 2014

Posted by **Amy** on Thursday, January 27, 2011 at 1:16pm.

log[1/3](x^(2) + x) - log[1/3] (x^(2) - x) = -1

Steps too please.

so far I tried this and I got 3 = (x+1) / (x-1)

- Precalc -
**bobpursley**, Thursday, January 27, 2011 at 1:51pmis that base 1/3? lets call that a.

loga(x^2+x) - loga(x^2-x)=-1

loga[(x^2+x)/(x^2-x)]=-1

take the antilog of each side, base a

(x+1)/(x-1)= a^-1

looks like you are correct.

**Related Questions**

Precalc - Solve for x log[1/3](x^(2) + x) - log[1/3] (x^(2) - x) = -1 Steps too ...

math - Logarithm!!! Select all of the following that are true statements: (a) ...

math - write as a single logarithm: -2logbase3(1/x)+(1/3)logbase3(square root of...

algebra homework - please check my answers. Solve the logarithmic equation. Be ...

Trig - log base b 64 - log base b 16 = log base 4 16 solve for the variable.. i...

Math Help Please - Which of the following expressions is equal to log (x sqrt-y...

TRig WIth LoGs help1!! - i have problem i can't solve and the book is no help.. ...

Advanced Functions/ Precalculus Log - 1. Evaluate 4^(log base4 64) + 10^(log100...

Precalc - how to write each expression into a single logarithm. 3log[4]x^(2) + (...

math - write as a single logarithm: ln(x/x-1)+ ln(x+1/x)- ln(x^2-1) please show ...