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April 16, 2014

April 16, 2014

Posted by **Amy** on Thursday, January 27, 2011 at 1:16pm.

log[1/3](x^(2) + x) - log[1/3] (x^(2) - x) = -1

Steps too please.

so far I tried this and I got 3 = (x+1) / (x-1)

- Precalc -
**bobpursley**, Thursday, January 27, 2011 at 1:51pmis that base 1/3? lets call that a.

loga(x^2+x) - loga(x^2-x)=-1

loga[(x^2+x)/(x^2-x)]=-1

take the antilog of each side, base a

(x+1)/(x-1)= a^-1

looks like you are correct.

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