joe has a mass of 50 kg and sally has a mads of 30 kg. they sit in class with a separation of 0.5 meters. Find hhe gravitational attraction between joe and sally
force=G50*30/.5^2 do the math.
r4r
To find the gravitational attraction between Joe and Sally, we can use Newton's Law of Universal Gravitation which states that the force of attraction between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
The equation to calculate the gravitational force (F) is given by:
F = (G * m1 * m2) / r^2
Where:
F = Gravitational force
G = Gravitational constant (approximately 6.67430 × 10^-11 Nm^2/kg^2)
m1 = Mass of Joe
m2 = Mass of Sally
r = Separation distance between Joe and Sally
Plugging in the values:
m1 = 50 kg
m2 = 30 kg
r = 0.5 meters
G = 6.67430 × 10^-11 Nm^2/kg^2
F = (6.67430 × 10^-11 Nm^2/kg^2) * (50 kg) * (30 kg) / (0.5 meters)^2
Now, let's calculate the gravitational force between Joe and Sally:
F = (6.67430 × 10^-11) * (50 kg) * (30 kg) / (0.5)^2
F = 2.00319 × 10^-9 N
Therefore, the gravitational attraction between Joe and Sally is approximately 2.00319 × 10^-9 Newtons.