A solution is prepared by mixing 5.00 grams of compound Z (molar mass 15.00 g/mol) in 100.0 ml of water. The density of the solution is 1.09 g/ml. Calculate the molarity of the solution

To calculate the molarity of the solution, we need to find the number of moles of compound Z in the solution and divide it by the volume of the solution in liters.

Step 1: Calculate the number of moles of compound Z.
Moles = mass / molar mass
Moles = 5.00 g / 15.00 g/mol
Moles = 0.333 mol

Step 2: Calculate the volume of the solution in liters.
Volume = mass / density
Volume = 100.0 ml * (1.00 g/ml / 1.09 g/ml)
Volume = 91.74 ml
Volume = 0.09174 L

Step 3: Calculate the molarity of the solution.
Molarity = moles / volume
Molarity = 0.333 mol / 0.09174 L
Molarity = 3.63 M

Therefore, the molarity of the solution is 3.63 M.

To calculate the molarity of the solution, we need to determine the number of moles of compound Z and the volume of the solution in liters.

1. Start by calculating the number of moles of compound Z:
- We are given the mass of compound Z as 5.00 grams and its molar mass as 15.00 g/mol.
- Use the formula: Number of moles = Mass / Molar mass
- Plug in the values: Number of moles = 5.00 g / 15.00 g/mol = 0.3333 mol (rounded to four decimal places).

2. Convert the volume of the solution from milliliters (ml) to liters (L):
- We are given the volume of the solution as 100.0 ml.
- Use the conversion factor: 1 L = 1000 ml
- Convert: Volume of solution = 100.0 ml / 1000 = 0.1000 L (rounded to four decimal places).

3. Now that we have the number of moles of compound Z and the volume of the solution in liters, we can calculate the molarity:
- Molarity = Number of moles / Volume of solution
- Substitute the values: Molarity = 0.3333 mol / 0.1000 L = 3.333 M (rounded to three decimal places).

Therefore, the molarity of the solution is approximately 3.333 M.