Posted by **steve** on Wednesday, January 26, 2011 at 11:27pm.

what is the formula to calculate the following:

how much force is needed to move a 10 pound block 10 feet in 8 seconds>

- physics -
**drwls**, Thursday, January 27, 2011 at 1:37am
Assuming there is no friction, proceed as follows.

The mass of the block is

M = W/g = 10/32.2 = 0.3106 slugs

Mass must be measured in slugs if you want the force in pounds, using Newton's second law.

The final velocity will have to be

2*10 ft/8 s = 2.5 ft/s to move 10 feet in 8 seconds. (The average velocity is half that, 1.25 ft/s)

The acceleration is

a = (2.5 ft/s)/8s = 0.3125 ft/s^2

Now use F = M a, with the mass M in slugs.

F = 0.097 pounds force

Look at it this way: You are accelerating the mass at about 1/100 g, so you need a force equal to only about 1/100 of the weight.

## Answer This Question

## Related Questions

- Physics/Force - building a device to shoote a plastic hockey puck with a lever (...
- Physics - A 2.8 kg block is pushed a distance D = 9.8 meters at a constant ...
- math - How much force is needed to accelerate a 50-kg rider and her 250-kg ...
- Re: Physics/Math - A 17 N horizontal force F pushes a block weighing 6.0 N ...
- Physics - A block (weight= 10kg) is sitting on a surface with friction (...
- physics - A 5.0-kg block is at rest on a horizontal floor. If you push ...
- physics - A 10.0-kg block is at rest on a horizontal floor. If you push ...
- physics PLEASE help - A 5.0-kg block is at rest on a horizontal floor. If you ...
- Physics - A block whose weight is 34.0 N rests on a horizontal table. A ...
- physics- please ! - A 3.0kg- block sits on top of a 5.0kg block which is on a ...

More Related Questions