Posted by Esther on Wednesday, January 26, 2011 at 11:14pm.
write an equation of the line containing the point and perpendicular to the given line (4,8); 2x+5y=4
I am having a very hard time, but I'm trying hard to study the steps for solving the problem.
Profoundly, thank you.

Algebra 1  helper, Wednesday, January 26, 2011 at 11:21pm
Did you see the answer to your post below?
Post your work so I can see where you are having trouble.

Algebra 1  Esther, Wednesday, January 26, 2011 at 11:49pm
Sorry, but, no, I didn't see the answer to my post. However,
(4,8); 2x+5y=4 is?
y=2x+4
y8=1/2
y8=1/2(x4)
Again, I don't really know what to do after this. I may not even be followin the steps right. However, I would really appreacite your help. Thank you a million.

Algebra 1  helper, Thursday, January 27, 2011 at 12:27am
2x + 5y = 4
Add 2x to both sides
5y = 2x + 4
divide both sides by 5
y = 2/5 y + 4/5
So, slope m = 2/5
Perpendicular lines, the slopes are negative reciprocals of each other.
Slope = 2/5
m1 * m2 = 1
2/5 * m2 = 1
m2 = 1/(2/5)
m2 = 5/2
Now you have to find b, for the equation of the perpendicular line.
y = mx + b
m = 5/2
y = 5/2 x + b
P(4, 8)
8 = 5/2 (4) + b
8 = 20/2 + b
8 = 10 + b
18 = b
y = 5/2 x + b
y = 5/2 + 18
y = 5/2  18
Follow these exact steps.
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