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A mono digital sound sample has a bit depth of 8 bits and a sampling rate of 9000 Hz. How much memory in bytes would it take to store 45 minutes of sound at this quality? Calculate your answer in bytes.

To calculate the amount of memory required to store the given sound sample, you need to consider the bit depth, sampling rate, and duration of the sound. Here's the step-by-step process:

1. Calculate the total number of bits used per second:
Multiply the bit depth by the sampling rate.
8 bits x 9000 Hz = 72,000 bits per second.

2. Convert the total number of bits to bytes:
Divide the total number of bits by 8 (since 1 byte = 8 bits).
72,000 bits / 8 = 9,000 bytes per second.

3. Multiply the bytes per second by the duration in seconds:
Convert the duration from minutes to seconds by multiplying by 60.
45 minutes x 60 seconds = 2,700 seconds.
9,000 bytes/second x 2,700 seconds = 24,300,000 bytes.

Therefore, it would take 24,300,000 bytes to store 45 minutes of sound at a bit depth of 8 bits and a sampling rate of 9000 Hz.