Posted by **Esther** on Wednesday, January 26, 2011 at 10:39pm.

write an equation of the line containing the given point and perpendicular to the given line (6,7);6x+=9

I am having a terrible time figuring out the last part. I would appreciate any help. Thank you.

- Algebra 1 -
**helper**, Wednesday, January 26, 2011 at 10:45pm
Your equation is not complete.

6x + = 9?

- Algebra 1 -
**Esther**, Wednesday, January 26, 2011 at 10:50pm
Sorry, I'm stressing badly. The equation is (6,7);6x+y=9. Thank you kindly.

- Algebra 1 -
**helper**, Wednesday, January 26, 2011 at 10:56pm
(6,7);6x+y=9.

y = mx + b

6x + y = 9

y = -6x + 9

m = -6

m1*m2 = -1

-6*m2 = -1

m2 = 1/6

So, the slope of the perpendicular line is 1/6.

y = 1/6 x + b

Now find b with point (6,7).

y = 1/6 x + b

7 = 1/6 (6) + b

7 = 6/6 + b

7 = 1 + b

b = 6

y = 1/6 x + b

y = 1/6 x + 6

- Algebra 1 -
**stefanie**, Thursday, January 27, 2011 at 3:10am
Was ist der dritte Teil von x?

- Algebra 1 -
**Anonymous**, Thursday, January 27, 2011 at 8:22pm
Stefanie, I need to turn in my homework today and i still need to solve this problem, can you please help me?(4,-8); 2x+5y=4

Thank you for your understanding.

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