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April 23, 2014

April 23, 2014

Posted by **Dolores** on Wednesday, January 26, 2011 at 7:38pm.

- Geometry -
**Reiny**, Wednesday, January 26, 2011 at 8:15pmLooks like the ambiguous case of the sine law.

let the angle opposite the 90 be Ø

sinØ/90 = sin 59/80

sinØ =.9643

Ø = 74.6 or 105.4°

so the third angle is

46.4° or 15.6°

now use the sine law for each case to find the two different possibilities for the third side.

There are two triangles possible with your given information, try sketching both using my answers.

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