A severe thunderstorm dumped 2.0 in of rain in 30 min on a town of area 50 km^2. What mass of water (in kg) fell on the town? One cubic meter of water has a mass of 103 kg.

To find the mass of water that fell on the town, we first need to find the volume of water that fell. We are given that the town has an area of 50 km^2 and that the rainfall was 2.0 inches. However, we need to convert the area and rainfall to the same units.

1 square kilometer (km^2) is equal to 1,000,000 square meters (m^2). Therefore, the town's area of 50 km^2 is equal to 50 * 1,000,000 = 50,000,000 m^2.

Next, we need to convert the rainfall from inches to meters. 1 inch is equal to 0.0254 meters, so the rainfall of 2.0 inches can be converted to 2.0 * 0.0254 = 0.0508 meters.

Now, we can find the volume of water that fell on the town by multiplying the area by the rainfall:

Volume = Area * Rainfall = 50,000,000 m^2 * 0.0508 m = 2,540,000 m^3

Finally, we can find the mass of water by multiplying the volume by the mass of 1 cubic meter of water:

Mass = Volume * Mass of 1 m^3 of water = 2,540,000 m^3 * 103 kg/m^3

Mass = 261,620,000 kg

Therefore, the mass of water that fell on the town is 261,620,000 kg.