Tuesday

August 4, 2015

August 4, 2015

Posted by **Esther** on Wednesday, January 26, 2011 at 5:44pm.

Thank you

- Algebra 1 -
**helper**, Wednesday, January 26, 2011 at 5:55pmEsther, see your post below at 3:11pm that I answered. I gave you detailed instructions on how to do this almost exact problem.

You will never learn without attempting the problem yourself.

Post all your work if your are stuck.

- Algebra 1 -
**Esther**, Wednesday, January 26, 2011 at 6:11pm(-8,6);2x=3y+4

I do understand the first part, but I still don't understand the second part. For instance,

3y=2x-4

y=(2/3)-4/3

the slope is 2/3

6=(2/3)(-8) this is where I'm getting stuck. I don't know if I should add, divide, or multiply these numbers to come up with the answer to the last part of the equation. I don't know what i'm doing wrong. I'm sorry, I really appreciate your patience and all your help.

- Algebra 1 -
**helper**, Wednesday, January 26, 2011 at 6:34pm(-8,6); 2x = 3y + 4

3y = 2x - 4

y =(2/3)x - 4/3

So, slope m = 2/3

Use y = mx + b and P(-8,6) to find the equation parallel

You know m = 2/3, so you have to find b.

y = 2/3 x + b

Put in x any y values and solve for b.

6 = 2/3 (-8) + b

See how my equation is different than yours? Where is the b in yours?

6 = 2/3 (-8) + b

6 = -16/3 + b

b = 6 + 16/3

b = 18/3 + 16/3

b = 34/3

y = 2/3 x + b

y = 2/3 x + 34/3

Check my arithmetic.

If it doesn't matter what form your new equation is in, then the above should be ok.

Hope this is clearer now.

- Algebra 1 -
**Esther**, Wednesday, January 26, 2011 at 6:56pmOH! Thank God, I think i got it,now I know what I was doing wrong. It only took me a few days to get it,(really bad)but, I think I got it. Of course, it takes practice, but I think I'll be ok, I'm gonna practice more and I should be ok, thanks to you. Thank you very, very much for clearing that up for me. God Bless you.

- Algebra 1 -
**Esther**, Wednesday, January 26, 2011 at 7:13pmIf it's not too much asking, can you please explain the same way with this problem?

(6,7);9x+y=6. It looks similar to the first problem, except that this one doesn't have a minus sign. Thank you, again for all your help. If I make it through college, it is going to be because of wonderful, caring people like yourself.

- Algebra 1 -
**helper**, Wednesday, January 26, 2011 at 7:21pmDo you need a line parallel to 9x + y = 6?

Or?

I'm happy you understand!! Good work.

- Algebra 1 -
**Esther**, Wednesday, January 26, 2011 at 7:25pmI'm sorry, I am so excited that I forgot to write what is needed for this problem.

Write an equation of the line containing the given point and perpendicular to the given line.

(6,7);9x+y=6

Thank you, again!

- Algebra 1 -
**helper**, Wednesday, January 26, 2011 at 8:48pm(6,7);9x+y=6

Put in y = mx + b form

9x + y = 6

y = -9x + 6

So slope m = -9

Perpendicular lines have slopes that are negative reciprocals of each other.

Meaning, m1 x m2 = -1

m1 = -9

-9 x m2 = -1

m2 = 1/9

So, the slope of the line will be 1/9

y = 1/9 x + b

To find b, P(6,7)

y = 1/9 x + b

7 = 1/9 (6) + b

7 = 6/9 + b

7 = 2/3 + b

b = 7 - 2/3

b = 21/3 - 2/3

b = 19/3

y = 1/9 x + b

y = 1/9 x + 19/3

Do you follow ?

- Algebra 1 -
**Anonymous**, Wednesday, January 26, 2011 at 9:50pmThank you for getting back to me. I seem to be having trouble figuring out the second part. For instance, I don't know how you went from 6/9 to 2/3. Also, I dont understand 7-2/3 or b= 21/3 - 2/3. I apologize, math is not my forte as you can see, i seem to learn much better step by step. I would really appreciate it if you can mention whether I should add, divide or multiply. However, since it is time consuming, if you can't, I will understand. Thank you for your patience and for all your help.

y = 1/9 x + b

7 = 1/9 (6) + b

7 = 6/9 + b

7 = 2/3 + b

b = 7 - 2/3

b = 21/3 - 2/3

b = 19/3