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Algebra 1

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Write an equation of the line containing the given point paralled to the given line (-8,6);2x=3y+4

Thank you

  • Algebra 1 - ,

    Esther, see your post below at 3:11pm that I answered. I gave you detailed instructions on how to do this almost exact problem.

    You will never learn without attempting the problem yourself.

    Post all your work if your are stuck.

  • Algebra 1 - ,

    (-8,6);2x=3y+4

    I do understand the first part, but I still don't understand the second part. For instance,

    3y=2x-4
    y=(2/3)-4/3

    the slope is 2/3

    6=(2/3)(-8) this is where I'm getting stuck. I don't know if I should add, divide, or multiply these numbers to come up with the answer to the last part of the equation. I don't know what i'm doing wrong. I'm sorry, I really appreciate your patience and all your help.

  • Algebra 1 - ,

    (-8,6); 2x = 3y + 4

    3y = 2x - 4
    y =(2/3)x - 4/3
    So, slope m = 2/3

    Use y = mx + b and P(-8,6) to find the equation parallel

    You know m = 2/3, so you have to find b.
    y = 2/3 x + b
    Put in x any y values and solve for b.
    6 = 2/3 (-8) + b
    See how my equation is different than yours? Where is the b in yours?

    6 = 2/3 (-8) + b
    6 = -16/3 + b
    b = 6 + 16/3
    b = 18/3 + 16/3
    b = 34/3

    y = 2/3 x + b
    y = 2/3 x + 34/3
    Check my arithmetic.

    If it doesn't matter what form your new equation is in, then the above should be ok.

    Hope this is clearer now.

  • Algebra 1 - ,

    OH! Thank God, I think i got it,now I know what I was doing wrong. It only took me a few days to get it,(really bad)but, I think I got it. Of course, it takes practice, but I think I'll be ok, I'm gonna practice more and I should be ok, thanks to you. Thank you very, very much for clearing that up for me. God Bless you.

  • Algebra 1 - ,

    If it's not too much asking, can you please explain the same way with this problem?

    (6,7);9x+y=6. It looks similar to the first problem, except that this one doesn't have a minus sign. Thank you, again for all your help. If I make it through college, it is going to be because of wonderful, caring people like yourself.

  • Algebra 1 - ,

    Do you need a line parallel to 9x + y = 6?

    Or?

    I'm happy you understand!! Good work.

  • Algebra 1 - ,

    I'm sorry, I am so excited that I forgot to write what is needed for this problem.

    Write an equation of the line containing the given point and perpendicular to the given line.
    (6,7);9x+y=6

    Thank you, again!

  • Algebra 1 - ,

    (6,7);9x+y=6

    Put in y = mx + b form
    9x + y = 6
    y = -9x + 6

    So slope m = -9

    Perpendicular lines have slopes that are negative reciprocals of each other.
    Meaning, m1 x m2 = -1

    m1 = -9
    -9 x m2 = -1
    m2 = 1/9

    So, the slope of the line will be 1/9
    y = 1/9 x + b

    To find b, P(6,7)
    y = 1/9 x + b
    7 = 1/9 (6) + b
    7 = 6/9 + b
    7 = 2/3 + b
    b = 7 - 2/3
    b = 21/3 - 2/3
    b = 19/3

    y = 1/9 x + b
    y = 1/9 x + 19/3

    Do you follow ?

  • Algebra 1 - ,

    Thank you for getting back to me. I seem to be having trouble figuring out the second part. For instance, I don't know how you went from 6/9 to 2/3. Also, I don't understand 7-2/3 or b= 21/3 - 2/3. I apologize, math is not my forte as you can see, i seem to learn much better step by step. I would really appreciate it if you can mention whether I should add, divide or multiply. However, since it is time consuming, if you can't, I will understand. Thank you for your patience and for all your help.

    y = 1/9 x + b
    7 = 1/9 (6) + b
    7 = 6/9 + b
    7 = 2/3 + b
    b = 7 - 2/3
    b = 21/3 - 2/3
    b = 19/3

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