Posted by Esther on Wednesday, January 26, 2011 at 5:44pm.
Write an equation of the line containing the given point paralled to the given line (8,6);2x=3y+4
Thank you

Algebra 1  helper, Wednesday, January 26, 2011 at 5:55pm
Esther, see your post below at 3:11pm that I answered. I gave you detailed instructions on how to do this almost exact problem.
You will never learn without attempting the problem yourself.
Post all your work if your are stuck. 
Algebra 1  Esther, Wednesday, January 26, 2011 at 6:11pm
(8,6);2x=3y+4
I do understand the first part, but I still don't understand the second part. For instance,
3y=2x4
y=(2/3)4/3
the slope is 2/3
6=(2/3)(8) this is where I'm getting stuck. I don't know if I should add, divide, or multiply these numbers to come up with the answer to the last part of the equation. I don't know what i'm doing wrong. I'm sorry, I really appreciate your patience and all your help. 
Algebra 1  helper, Wednesday, January 26, 2011 at 6:34pm
(8,6); 2x = 3y + 4
3y = 2x  4
y =(2/3)x  4/3
So, slope m = 2/3
Use y = mx + b and P(8,6) to find the equation parallel
You know m = 2/3, so you have to find b.
y = 2/3 x + b
Put in x any y values and solve for b.
6 = 2/3 (8) + b
See how my equation is different than yours? Where is the b in yours?
6 = 2/3 (8) + b
6 = 16/3 + b
b = 6 + 16/3
b = 18/3 + 16/3
b = 34/3
y = 2/3 x + b
y = 2/3 x + 34/3
Check my arithmetic.
If it doesn't matter what form your new equation is in, then the above should be ok.
Hope this is clearer now. 
Algebra 1  Esther, Wednesday, January 26, 2011 at 6:56pm
OH! Thank God, I think i got it,now I know what I was doing wrong. It only took me a few days to get it,(really bad)but, I think I got it. Of course, it takes practice, but I think I'll be ok, I'm gonna practice more and I should be ok, thanks to you. Thank you very, very much for clearing that up for me. God Bless you.

Algebra 1  Esther, Wednesday, January 26, 2011 at 7:13pm
If it's not too much asking, can you please explain the same way with this problem?
(6,7);9x+y=6. It looks similar to the first problem, except that this one doesn't have a minus sign. Thank you, again for all your help. If I make it through college, it is going to be because of wonderful, caring people like yourself. 
Algebra 1  helper, Wednesday, January 26, 2011 at 7:21pm
Do you need a line parallel to 9x + y = 6?
Or?
I'm happy you understand!! Good work. 
Algebra 1  Esther, Wednesday, January 26, 2011 at 7:25pm
I'm sorry, I am so excited that I forgot to write what is needed for this problem.
Write an equation of the line containing the given point and perpendicular to the given line.
(6,7);9x+y=6
Thank you, again! 
Algebra 1  helper, Wednesday, January 26, 2011 at 8:48pm
(6,7);9x+y=6
Put in y = mx + b form
9x + y = 6
y = 9x + 6
So slope m = 9
Perpendicular lines have slopes that are negative reciprocals of each other.
Meaning, m1 x m2 = 1
m1 = 9
9 x m2 = 1
m2 = 1/9
So, the slope of the line will be 1/9
y = 1/9 x + b
To find b, P(6,7)
y = 1/9 x + b
7 = 1/9 (6) + b
7 = 6/9 + b
7 = 2/3 + b
b = 7  2/3
b = 21/3  2/3
b = 19/3
y = 1/9 x + b
y = 1/9 x + 19/3
Do you follow ? 
Algebra 1  Anonymous, Wednesday, January 26, 2011 at 9:50pm
Thank you for getting back to me. I seem to be having trouble figuring out the second part. For instance, I don't know how you went from 6/9 to 2/3. Also, I don't understand 72/3 or b= 21/3  2/3. I apologize, math is not my forte as you can see, i seem to learn much better step by step. I would really appreciate it if you can mention whether I should add, divide or multiply. However, since it is time consuming, if you can't, I will understand. Thank you for your patience and for all your help.
y = 1/9 x + b
7 = 1/9 (6) + b
7 = 6/9 + b
7 = 2/3 + b
b = 7  2/3
b = 21/3  2/3
b = 19/3