if 6 bugs are in a cage and you take away 70 but you need to divide that by 3, how many bugs would be left?

Please clarify your problem.

How many bugs did you start with again please?

To determine how many bugs would be left, let's break down the given information step by step.

Step 1: Start with 6 bugs in the cage.
Step 2: Take away 70 from the number of bugs.
Step 3: Divide the result by 3 to find the final number of bugs.

Now, let's calculate each step:

Step 1: Start with 6 bugs.
Step 2: Take away 70 from the number of bugs.
6 - 70 = -64
Step 3: Divide the result by 3.
-64 ÷ 3 = -21.333...

Based on the calculations, we ended up with a negative number of -21.333... bugs. Since you can't have a fraction of a bug, the concept of negative bugs is also not possible. Therefore, there would be zero bugs left in the cage.