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physics

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An 82 kg man lowers himself to the ground from a height of 6.6 m by holding onto a rope that runs over a frictionless pulley to a 66 kg sandbag. With what speed does the man hit the ground if he started from rest?

  • physics -

    Force up on 66 kg mass = T
    Force down on 66 kg mass = 66(9.8 )
    net force up on 66 kg = T-66(9.8)
    F = m a
    T -66(9.8) = 66 a
    a is down

    Force down on 82 kg mass = 82(9.8)
    Force up on 82 kg mass = T
    net force down on 82 kg = 82(9.8) -T
    F = m a
    82(9.8) - T = 82 a
    combine by addition
    (82-66)(9.8) = (82+66) a
    solve for a which is down
    then
    6.6 = (1/2) a t^2
    solve for t
    then v = a t

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