How to solve this??? The attendance at the game on two successive nights of Oakland A's baseball was 77,000. The attendance on Thursday's game was 7000 more than two thirds of the attendance at Friday nights game. How many people attended the baseball game each night?

x = attendance at Friday's game

2/3 x + 7000 = attendance at Thursday's game

x + 2/3 x + 7000 = 77000
Solve for x - Fri
2/3 x + 7000 - Thur

the attendance on the first night of a play was 435. The attendance of on the third night was 545. if the attendance increase at a linear rate, then how many people can be expected to show up on the 6th night

The attendance at two baseball games on successive nights was 78 comma 00078,000. The attendance on​ Thursday's game was 80008000 more than​ two-thirds of the attendance at Friday​ night's game. How many people attended the baseball game each​ night?

To solve this problem, let's break it down step by step:

1. Let's assume the attendance at Friday night's game is represented by the variable "x" (in thousands). So, the attendance at Thursday night's game would be (2/3)x + 7000.

2. According to the problem, the total attendance for both nights is 77,000 (in thousands). So, we can write the equation: x + (2/3)x + 7000 = 77,000.

3. Now, we can solve the equation to find the value of x. First, simplify the equation: (5/3)x + 7000 = 77,000.

4. Subtract 7000 from both sides of the equation: (5/3)x = 70,000.

5. Multiply both sides of the equation by 3/5 to isolate x: x = (70,000 * 3/5) = 42,000.

6. Therefore, the attendance at Friday night's game was 42,000 (in thousands), and the attendance at Thursday night's game was (2/3) * 42,000 + 7000 = 35,000 (in thousands).

So, there were 42,000 people at Friday night's game and 35,000 people at Thursday night's game.