A 55.0-kg skydiver free falls for a period of time before opening his parachute. What is his kinetic energy when he reaches a velocity of 16.0 meters/second?

Good grief. Enough, already. Do the calculation yourself. The equation has already been provided.

use 1/2mv^2

(1/2)(55)(16)^2=7040 J

To calculate the kinetic energy of the skydiver, we need to use the equation for kinetic energy:

Kinetic Energy = 1/2 * mass * velocity^2

Given:
Mass (m) = 55.0 kg
Velocity (v) = 16.0 m/s

Now, we can substitute the values into the equation and calculate the kinetic energy:

Kinetic Energy = 1/2 * 55.0 kg * (16.0 m/s)^2

Let's solve it step by step:

Step 1: Calculate the square of the velocity
(16.0 m/s)^2 = 256.0 m^2/s^2

Step 2: Multiply the result by half of the mass
1/2 * 55.0 kg * 256.0 m^2/s^2 = 7040.0 Joules

So, when the skydiver reaches a velocity of 16.0 meters/second, his kinetic energy is 7040.0 Joules.