2 x dx + 8 y dy = 3x dy + 3y dx
Where is the slope = 0?
where 2x = 3y
if x = 3
9 + 4 y^2 = 7 + 9 y
4 y^2 - 9 y + 2 = 0
(4y-1)(y-2) = 0
y = 1/4 or y = 2
check both of those to find which works
3*2 - 2*3 = 0
yes, (3,2) works
3/4 -6 = 0 no way so (3,2) is it
d^2y/dx^2 = [(8y-3x)(-2)-(3y-2x)(-3)] / (8y-3x)^2
= [(16-9)(-2)]/(16-9)^2 = -2/7
that is negative, so a maximum of the function
Thank you so much! It makes perfect sense and when I calculated it, it matched up.
I'm confused as to how to do part C), I don't remember how to find the second derivative of an implicit differentiation problem!
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