Nico is saving money for his college education. He invest some money at 8%, and $1300 less than that amount at 5%. the investments produced a total of $234 intrest in 1 yr.How much did he invest at each rate?

.08(x)+.05(x-1300)=234 solve for x

.08x+.05x-65=234
x=2300

to check your answer
.08(2300)=184
.05(2300-1300)=50
184+50=234

I could have helped earlier if you posted the subject.

To solve this problem, we can set up two equations based on the given information.

Let's say the amount Nico invested at 8% is x dollars. Therefore, the amount he invested at 5% would be (x - $1300) dollars.

We know that the interest from the investments is $234 in total. The interest from the amount invested at 8% is 8% of x, which is 0.08x. The interest from the amount invested at 5% is 5% of (x - $1300), which can be written as 0.05(x - $1300).

Based on the above information, we can write the equation:

0.08x + 0.05(x - $1300) = $234

Now let's solve for x:

0.08x + 0.05x - 0.05($1300) = $234

0.13x - $65 = $234

0.13x = $234 + $65

0.13x = $299

x = $299 / 0.13

x ≈ $2300

Therefore, Nico invested approximately $2300 at 8% and $2300 - $1300 = $1000 at 5%.