Posted by **Melody** on Wednesday, January 26, 2011 at 2:12pm.

In a triangle PQR, angle Q=50 degrees,PR=5CM, QR=4CM. find angle P?

- trigonometry. Math -
**Reiny**, Wednesday, January 26, 2011 at 2:23pm
Looks like the "ambiguous case" , or sometimes called the SSA setup, where A is NOT the contained angle

sinP/4 = sin 50°/5

sin P = 4sin50/5 = .61284

angle P = 37.8° or 180-37.8 ° which is 142.2°

but the second case would result in (angleR + 142.2+50) > 180, thus that case is not admissable.

so angle P is 37.8°

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