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March 26, 2017

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In a triangle PQR, angle Q=50 degrees,PR=5CM, QR=4CM. find angle P?

  • trigonometry. Math - ,

    Looks like the "ambiguous case" , or sometimes called the SSA setup, where A is NOT the contained angle

    sinP/4 = sin 50°/5
    sin P = 4sin50/5 = .61284
    angle P = 37.8° or 180-37.8 ° which is 142.2°

    but the second case would result in (angleR + 142.2+50) > 180, thus that case is not admissable.

    so angle P is 37.8°

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