Posted by PLEASE HELP!!! on Wednesday, January 26, 2011 at 1:58pm.
Two planes leave an airport at the same time, one flying east, the other flying west.The eastbound plane travels 100 mph slower. They are 3040mi apart after 4hrs. find the speed of each plane

MATH  Reiny, Wednesday, January 26, 2011 at 2:11pm
let speed of slower plane be x mph
then speed of faster plane is x+100 mph
solve for x
4x + 4(x+100) = 3040

MATH  Tristan, Wednesday, January 26, 2011 at 2:27pm
I got x=330 what do i do from there. How do i get the speed of each plane from there?

MATH  Reiny, Wednesday, January 26, 2011 at 2:57pm
I defined x as the speed of the slower speed
so the slower plane has speed of 330 mph
I defined x+100 as the speed of the faster plane, so
faster plane goes (330+100) or 430 mph
check:
what is 4(330) + 4(430) ?

MATH  Tristan, Wednesday, January 26, 2011 at 3:02pm
3040...okay thanks
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