Posted by **PLEASE HELP!!!** on Wednesday, January 26, 2011 at 1:58pm.

Two planes leave an airport at the same time, one flying east, the other flying west.The eastbound plane travels 100 mph slower. They are 3040mi apart after 4hrs. find the speed of each plane

- MATH -
**Reiny**, Wednesday, January 26, 2011 at 2:11pm
let speed of slower plane be x mph

then speed of faster plane is x+100 mph

solve for x

4x + 4(x+100) = 3040

- MATH -
**Tristan**, Wednesday, January 26, 2011 at 2:27pm
I got x=330 what do i do from there. How do i get the speed of each plane from there?

- MATH -
**Reiny**, Wednesday, January 26, 2011 at 2:57pm
I defined x as the speed of the slower speed

so the slower plane has speed of 330 mph

I defined x+100 as the speed of the faster plane, so

faster plane goes (330+100) or 430 mph

check:

what is 4(330) + 4(430) ?

- MATH -
**Tristan**, Wednesday, January 26, 2011 at 3:02pm
3040...okay thanks

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