Posted by **Conder** on Wednesday, January 26, 2011 at 12:15pm.

The highest dive in the Olympic Games is from a 10-meter platform. The height "h" is in meters of a diver "t" seconds after leaving the platform can be estimated by the equation, h=10+4.9t-4.9t^2

I don't know how to make a successful table for this. I tried 0.1, 0.2, etc.. but that doesn't seem to work.

- Math -
**Reiny**, Wednesday, January 26, 2011 at 2:06pm
when t=.1 , h = 10 + 4.9(.1) - 4.9(.1)^2 =10.441

when t= .2 , h= 10 + 4.9(.2) - 4.9(.2)^2 = 10.784

what do you mean it "doesn't seem to work" ?

He clearly jumps upwards for a short time before his height decreases.

Just keep going the way I showed you.

- Math -
**tchrwill**, Wednesday, January 26, 2011 at 2:30pm
The general equation for the height of an object falling from a height of H is

h = H - Vot - 9.8t^2/2 where H = the initial height in meters, Vo = the initial downward velocity in m/sec., 9.8 = the acceleration due to gravity in m/sec.^2 and t = the time to impact in seconds.

Your equation should therefore read

h=10-4.9t-4.9t^2, where I assume you have selected H = 10 and Vo as 4.9 m/s.

For t = .10, h = 10 - .49 - .049 = 9.461m.

For t = .20, h = 10 - .98 - .196 = 8.824m.

For t = .30, h = 10 - 1.47 - .441 = 8.089m.

t----.10----.20---.30------1.973

h...9.461..8.824..8.089.....10

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