how many mL of watel should be added to yeild a soultion that has a concentration of .125 M when you start with a 250 mL soultion of 1 M AgNO3?

To find out how many milliliters (mL) of water should be added to yield a solution with a concentration of 0.125 M, you need to use the dilution formula. The dilution formula is:

C1V1 = C2V2

Where:
C1 is the initial concentration of the solution (1 M, in this case)
V1 is the initial volume of the solution (250 mL, in this case)
C2 is the final concentration of the solution (0.125 M, in this case)
V2 is the final volume of the solution (unknown, we need to find this)

Let's plug the values we know into the formula:

(1 M)(250 mL) = (0.125 M)(V2)

To solve for V2, we can rearrange the equation:

V2 = (1 M)(250 mL) / (0.125 M)

V2 = (1)(250) / (0.125)

V2 = 2000 mL

Therefore, to yield a solution with a concentration of 0.125 M, you would need to add 2000 mL of water to the 250 mL solution of 1 M AgNO3.