What is the volume, in mL of .089 m lithium chloride (LiCl) solution containing 4.3g of LiCl???
To find the volume of the lithium chloride (LiCl) solution, we need to use the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's calculate the number of moles of LiCl in the solution using the given mass and the molar mass of LiCl:
1. Calculate the molar mass of LiCl:
- Molar mass of lithium (Li) = 6.94 g/mol
- Molar mass of chlorine (Cl) = 35.45 g/mol
- Molar mass of LiCl = (6.94 g/mol) + (35.45 g/mol) = 42.39 g/mol
2. Convert the given mass of LiCl from grams to moles:
- Moles of LiCl = mass of LiCl / molar mass of LiCl
- Moles of LiCl = 4.3 g / 42.39 g/mol
Now, we have the number of moles of LiCl in the solution. To determine the volume of the solution in milliliters (mL), we need to rearrange the equation mentioned earlier.
3. Rearrange the equation to solve for the volume of solution (V):
- V = moles of solute / Molarity
4. Molarity (M) is given as 0.089 m. Remember that molarity is the number of moles of solute per liter of solution.
Now, let's substitute the values and calculate the volume of the solution:
V = (4.3 g / 42.39 g/mol) / 0.089 mol/L
Here we have everything we need to calculate the volume of the LiCl solution.