What is the nuber of grams of oxygen present in 4.50 x 10^22 SO3 moleucles?
To find the number of grams of oxygen present in 4.50 x 10^22 SO3 molecules, we need to use the concept of molar mass and stoichiometry.
Step 1: Find the molar mass of SO3.
The molar mass of S is 32.06 g/mol, and the molar mass of O is 16.00 g/mol. Since there are three oxygen atoms in one SO3 molecule, we can calculate the molar mass of SO3 as follows:
Molar mass of SO3 = (1 * molar mass of S) + (3 * molar mass of O)
= (1 * 32.06 g/mol) + (3 * 16.00 g/mol)
= 32.06 g/mol + 48.00 g/mol
= 80.06 g/mol
Step 2: Calculate the number of moles of SO3.
Given that there are 4.50 x 10^22 SO3 molecules, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of moles:
Number of moles of SO3 = (number of molecules) / (Avogadro's number)
= (4.50 x 10^22 molecules) / (6.022 x 10^23 molecules/mol)
= 0.0747 mol
Step 3: Determine the number of grams of oxygen.
Since there are three oxygen atoms in one SO3 molecule and each oxygen atom has a molar mass of 16.00 g/mol, we can calculate the number of grams of oxygen as follows:
Number of grams of oxygen = (number of moles of SO3) * (3 * molar mass of O)
= (0.0747 mol) * (3 * 16.00 g/mol)
= 0.0747 mol * 48.00 g/mol
= 3.58 g
Therefore, the number of grams of oxygen present in 4.50 x 10^22 SO3 molecules is 3.58 grams.