What are the number of atoms of nitrogen in 10g of N2H4?
To find the number of atoms of nitrogen in 10g of N2H4, we need to use the Avogadro's number and the molar mass of N2H4.
Step 1: Calculate the molar mass of N2H4
To calculate the molar mass of N2H4, we sum up the atomic masses of its constituent elements, which are nitrogen (N) and hydrogen (H).
- The atomic mass of nitrogen (N) is approximately 14.01 g/mol.
- The atomic mass of hydrogen (H) is approximately 1.01 g/mol.
So, molar mass of N2H4 = (2 * atomic mass of N) + (4 * atomic mass of H)
= (2 * 14.01 g/mol) + (4 * 1.01 g/mol)
= 32.05 g/mol
Step 2: Determine the number of moles of N2H4
To find the number of moles of N2H4, we use the formula:
moles = mass / molar mass
moles of N2H4 = 10g / 32.05 g/mol
≈ 0.312 moles
Step 3: Determine the number of nitrogen atoms
Since there are two nitrogen atoms in one molecule of N2H4, we multiply the number of moles of N2H4 by 2:
number of nitrogen atoms = moles of N2H4 * Avogadro's number * 2
Avogadro's number is approximately 6.022 x 10^23.
number of nitrogen atoms ≈ 0.312 moles * (6.022 x 10^23 atoms/mol) * 2
≈ 3.74 x 10^23 atoms
Therefore, there are approximately 3.74 x 10^23 atoms of nitrogen in 10g of N2H4.