Posted by jr on Wednesday, January 26, 2011 at 11:45am.
(a) Add the water velocity vector to the boat velocity vector with respect to the water. Get the magnitude of the resultant, sqrt (Vx^2 + Vy^2)
Vx is the downstream component (east), Vy is the cross-stream component (north)
(b) Get the direction of the resultant. It is the arctangent of the
Vx/Vy ratio
(c) Time to cross = (River width)/Vy
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