Find the x-intercept
3x-5y=14y+9x
I think y=0 but 3x=9x does not make sense to me.
Please help me. Thank you.
Error:your Eq does not have a constant.
So I'm going to solve it with the assumption that 9x was meant to be 9.
In the meantime you should check your
Eq and repost if neccessary.
3X - 5Y = 14Y + 9.
3X - 5Y - 14Y = 9,
3X - 19Y = 9,
To find X-Int,let y = 0 and solve for
X:
3X - 19*0 = 9,
3X = 9,
X = 9 / 3 = 3 = X-Int.
To find the x-intercept, we need to find the value of x when y is equal to zero. Let's start by rearranging the equation to isolate x.
Given: 3x - 5y = 14y + 9x
First, let's simplify the equation by combining like terms:
3x - 9x = 14y + 5y
-6x = 19y
Now, since we want to find the x-intercept (where y = 0), we can substitute y = 0 into the equation:
-6x = 19(0)
Simplifying further:
-6x = 0
To solve for x, divide both sides of the equation by -6:
x = 0 / -6
Therefore, the x-intercept is x = 0.
Note that it is possible for an equation to have a y-intercept but no x-intercept or vice versa. In this case, the x-intercept exists because we found an x value when y is equal to zero.