Posted by **mely** on Wednesday, January 26, 2011 at 1:02am.

A daring 510 { N} swimmer dives off a cliff with a running horizontal leap, as shown in the figure below.

What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1.75 {m} wide and 9.00 {m} below the top of the cliff?

- physics -
**drwls**, Wednesday, January 26, 2011 at 5:41am
Calculate the time to fall 9.00 meters, and call it T

T = sqrt (2H/g)= 1.355 s

Require that

V* T > 1.75 m

Vmin occurs when V = (1.75 m)/T

= 1.29 m/s

- physics -
**Henry**, Thursday, January 27, 2011 at 8:17pm
mely, check your 1-26,12:52am post.

## Answer this Question

## Related Questions

- physics - What must her minimum speed be just as she leaves the top of the cliff...
- physics - A boulder rolls off a cliff that is 20 m above the surface of a lake ...
- Wile E. Coyote - The determined Wile E. Coyote is out once more to try to ...
- Physics - A stunt driver wants to make his car jump over 8 cars parked side by ...
- physics - A diver running 1.89 m/s dives out horizontally from the edge of a ...
- physics - A diver running 2.4 m/s dives out horizontally from the edge of a ...
- physics - A student stands at the edge of a cliff and throws a stone ...
- Physics - Augustine continues to run around. He gets to the park and has the ...
- Physics - Augustine continues to run around. He gets to the park and has the ...
- physics - Consider a swimmer who wants to swim directly across a river as shown ...

More Related Questions